Working with series
What is a series?
A series in DataMatrix is a type of column, a SeriesColumn in which each cell is itself a series of values.
Mixing two- and three-dimensional data
With column-based, or tabular, data every cell is defined by two coordinates: the column name, and the row number; that is, column-based data is two dimensional. But for many kinds of data, two dimensions is not enough.
To illustrate this, let's imagine that you want to store the population of cities over a period of three years. You could do this by simply adding a column for every year, population2008, population2009, population2010:
from datamatrix import DataMatrix
# Not very elegant!
dm = DataMatrix(length=2)
dm.city = 'Marseille', 'Lyon'
dm.population2010 = 850726, 484344
dm.population2009 = 850602, 479803
dm.population2008 = 851420, 474946
print(dm)
Output:
+---+-----------+----------------+----------------+----------------+
| # | city | population2008 | population2009 | population2010 |
+---+-----------+----------------+----------------+----------------+
| 0 | Marseille | 8.514200E+05 | 8.506020E+05 | 8.507260E+05 |
| 1 | Lyon | 4.749460E+05 | 4.798030E+05 | 4.843440E+05 |
+---+-----------+----------------+----------------+----------------+
In this example, this approach is feasible, because there are only three years, so you need only three columns. But imagine that you want to store the year-by-year population over several centuries. You would then end up with hundreds of columns! Not impossible, but not very elegant either.
It would be much more elegant if you could have a single column for the population, and then give this column a third dimension (a depth) so that it can store the population over time. And that's where the SeriesColumn comes in.
from datamatrix import DataMatrix, SeriesColumn
# Pretty elegant, right?
dm = DataMatrix(length=2)
dm.city = 'Marseille', 'Lyon'
dm.population = SeriesColumn(depth=3)
dm.population[0] = 850726, 850602, 851420 # Marseille
dm.population[1] = 484344, 479803, 474946 # Lyon
dm.year = SeriesColumn(depth=3)
dm.year = 2010, 2009, 2008
print(dm)
Output:
+---+-----------+---------------------------+---------------------+
| # | city | population | year |
+---+-----------+---------------------------+---------------------+
| 0 | Marseille | [850726. 850602. 851420.] | [2010. 2009. 2008.] |
| 1 | Lyon | [484344. 479803. 474946.] | [2010. 2009. 2008.] |
+---+-----------+---------------------------+---------------------+
Basic properties of series
SeriesColumns have the same properties as regular columns: mean, median, std, sum, min, and max. But where these properties are single values for regular columns, they are iterators for SeriesColumns (a one-dimensional numpy array, to be exact).
print(dm.population.mean)
Output:
[667535. 665202.5 663183. ]
Indexing
Accessing
The first dimension of a SeriesColumn refers to the row. So to get the population of Marseille (row 0) over time, you can do:
print(dm.population[0])
Output:
[850726. 850602. 851420.]
The second dimension refers to the depth. So to get the population of both Marseille and Lyon in 2009, you can do:
print(dm.population[:,1])
Output:
[850602. 479803.]
Assigning
You can assign to a SeriesColumn as you would to a 2D numpy array:
dm = DataMatrix(length=2)
dm.s = SeriesColumn(depth=3)
dm.s[0,0] = 1
dm.s[1:,1:] = 2
print(dm)
Output:
+---+---------------+
| # | s |
+---+---------------+
| 0 | [ 1. nan nan] |
| 1 | [nan 2. 2.] |
+---+---------------+
If you want to set all cells at once, you can directly assign a single value:
dm.s = 10
print(dm)
Output:
+---+---------------+
| # | s |
+---+---------------+
| 0 | [10. 10. 10.] |
| 1 | [10. 10. 10.] |
+---+---------------+
If you want to set all rows at once, you can directly assign a sequence with a length that is equal to the depth of the series:
dm.s = 100, 200, 300
# Equal to: dm.s[:,:] = 100, 200, 300
print(dm)
Output:
+---+------------------+
| # | s |
+---+------------------+
| 0 | [100. 200. 300.] |
| 1 | [100. 200. 300.] |
+---+------------------+
If you want to set all columns at once, you can directly assing a sequence with a length that is equal to the length of the DataMatrix:
dm.s = 1000, 2000
# Equal to: dm.s[:,:] = 1000, 2000
print(dm)
Output:
+---+---------------------+
| # | s |
+---+---------------------+
| 0 | [1000. 1000. 1000.] |
| 1 | [2000. 2000. 2000.] |
+---+---------------------+